Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of
(– 3, – 25), and x intercepts at x = -8 and x = 2. (Do not include the negative sign in your answer.)

y = x2 + 6x − ___

Numerical Answers Expected!

Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of 
(– 3, – 25), and x intercepts at x = -8 and x = 2. (Do not include the negative sign in your answer.) 

y = x2 + 6x −  ___

Numerical Answers Expected!

anonymous · Answer

If it has x-intercepts at -8 and 2 then two of its factors are (x+8)(x-2). -->  (x+8)(x-2)=x^2+6x-16. Remember the equation we need starts with x^2+6x-___ so the missing term is -16. Since it says don't include the negative in the anxwer the answer is 16. You did not even need the vertex to solve this.

anonymous · Answer

Thank you^^