Ask
your own question, for FREE!
Ask question now!
Mathematics
35 Online
OpenStudy (anonymous):
Please check
12 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
So I got \[10\sqrt{3}\]
12 years ago
OpenStudy (apoorvk):
That's for 'x' or 'y'?
12 years ago
OpenStudy (hba):
^^ same question
12 years ago
OpenStudy (anonymous):
wait its 10
12 years ago
OpenStudy (hba):
^^ what is 10
12 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (zepp):
Sin Opposite/Hypotenuse
Cos Adjacent/Hypotenuse
Tan Opposite/Adjacent
12 years ago
OpenStudy (zepp):
|dw:1342465958208:dw|
12 years ago
OpenStudy (apoorvk):
Okay Trexy, 10 and 10sqrt3 ARE answers, but which one for x and which one for y?
12 years ago
OpenStudy (anonymous):
idk..
12 years ago
OpenStudy (anonymous):
i mean I dont know wat you mean
12 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
its asking for x? so Idk which one
12 years ago
OpenStudy (anonymous):
@agentx5
12 years ago
OpenStudy (diyadiya):
@Trexy you have to find both x and y
12 years ago
OpenStudy (diyadiya):
\[\sin30^\circ = \frac{opposite~side}{hypotenuse}\]\[\sin30^\circ = \frac{x}{20}\]\[\frac{1}{2} = \frac{x}{20}\] \[x=10\]
12 years ago
OpenStudy (anonymous):
|dw:1342471899864:dw|
SOH-CAH-TOA:
SOH : \(\sin \theta = \large \frac{opposite}{hypotenuse} \)
CAH : \(\cos \theta = \large \frac{adjacent}{hypotenuse} \)
TOA : \(\tan \theta = \large \frac{opposite}{adjacent} \)
@Trexy, first identify the two for me. Give than angle, which trig function involves y & 20? And which involves x & 20?
12 years ago
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours! Join our real-time social learning platform and learn together with your friends!
Sign Up
Ask Question