3x+2[3x+18]=12x --> 3x+6x+36=12x --> 9x+36=12x --> subtract 9x from both "/> 3x+2[3x+18]=12x --> 3x+6x+36=12x --> 9x+36=12x --> subtract 9x from both "/> 3x+2[3x+18]=12x --> 3x+6x+36=12x --> 9x+36=12x --> subtract 9x from both "/> 3x+2[3x+18]=12x --> 3x+6x+36=12x --> 9x+36=12x --> subtract 9x from both "/>
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Mathematics 18 Online
OpenStudy (anonymous):

Solve and check: 3x +2 [3(x+6)] = 12x I was givein this: "3x +2 [3(x+6)] = 12x --> 3x+2[3x+18]=12x --> 3x+6x+36=12x --> 9x+36=12x --> subtract 9x from both sides of the equation. 36=3x --> divide by 3. 12=x {finished}! then you just plug 12 back in the equation wherever there is an x. Work it until you get one number equals itself example: 112=112" Now i'm having trouble checking it. I keep getting 144=112 Can someone PLZ help?

OpenStudy (anonymous):

its 144 on both sides

OpenStudy (anonymous):

|dw:1342467731752:dw|

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