Question

Solve using any method. x² + 4x - 32 = 0

Answer 1

It factors!

Watch...

Answer 2

what two factor of 32 will add or subtract to give you 4

Answer 3

-32=8*(-4)

Answer 4

so \[x ^{2}+4x-32=0\]
can be changed into

(x+8)*(x-4)=0

Answer 5

my method is to watch what everyone gets...:)

Answer 6

32 = 2 * 2 * 2 * 2 * 2
Seeing as there's a - in the last term, that means you're going to have a + and a - when you factor...
2*2*2 - 2*2
8 - 4
4

\[(x-4) (x+8) = 0\]
solve each one now
\[x-4=0 \rightarrow x=4\]
\[x+8=0 \rightarrow x=-8\]