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OpenStudy (anonymous):
factor 250x^4-2x
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OpenStudy (anonymous):
take 2x common 2x(125x^3-1) 2x((5x0^3-1^3) 2x(5x-1)(25x^2+5x+1) using \[a^3-b^3=(a-b)(a^2+ab+b^2)\]
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