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How many different pizza's can be ordered if the restaurant offers 15 different toppings and there is not limit to the number of toppings on the pizza? Okay, so I know that the answer is 32768. But I'm just not positive how to get to that, could someone please explain?
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pizzas *
k wait a sec
yup
sorry couldnt get it
@Compassionate help needed
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Ther is no upper limit means it could go upto infinity..
Otherwise I guess it's a combination problem.
15 different toppings. 15(bits) \[(2^5)^3 = 32^3 = 32,768\]
u can also do it this way: [although its reeeally lengthy!] 15C1 + 15C2 + 15C3 +........+ 15C14 + 16C15
sorry, the last term should be 15C15
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thanks :D !!!
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