Question

The Perimeter of a rectangle is 52. Its length is 2 more than twice the measure of its width. find its dimensions.

Answer 1

Equation:
52 = 2(2w + 2) + 2w

Answer 2

Distribute the 2 outside the parentheses to both terms INSIDE the parentheses.

Afterwards combine like terms. Solve for w.

What ever you get for w, plug it into the equation below for w:

L = 2(w) + 2

Answer 3

thanks a lot

Answer 4

No problem. Take care

Answer 5

perimeter ofrectangle=2(l+b)
as l=2b
per=2(3b)=52
6b=52
b=52/6
b=8.6
l=2b
l=2(8.6)
l-17.8

Answer 6

length=17.8 breadth=8.67