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Solve the system of equations. -2x + 3y = 8 3x – y = -5
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multiply second equation by 3 add the two together
Try this: Multiply the second by 3. Add it the the first one. tell us what do you get.
how do i set that up?
Like this: 1st :-2x+3y=8 2nd*(3) : 9x-3y=-15
Now add them. Tell us what do you get.
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\[-2x + 3y = 8\]\[ 3x – y = -5\] \[-2x+3y=8\]\[3(3x-y)=3(-5)\] \[-2x+3y=8\]\[9x-3y=-15\] add to get \[7x=-7\]solve for \(x\)\[7x=-7\implies x=-1\]
y=3x+5 Substitute this value in eq 1
thankss
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