Question

6t^2+23t-4=0 how do you solve this problem?

Answer 1

I'm using the ac method

Answer 2

what do u want to solve for

Answer 3

6t^2 + 23t - 4 =0
product of the two roots = 6x -4 = -24
sum of two roots = 23
am thinking of 24 and -1
6t^2 + 23t - 4 =0
breaking the middle term
6t^2 +24t - t - 4 = 0
factoring
6t (t+4) -1( t+4) = 0
(6t-1) (t+4) =0
therefore:
6t-1 = 0 and t = 1/6
or
t+4 = 0 and t =-4
solution for t = (1/6, -4)

Answer 4

I'm sorry I'm little confused how did you get your answer?

Answer 5

Never I see how you got it.

Answer 6

*mind

Answer 7

good

Answer 8

Thank you.