Your school drama club is putting on a play and hopes to raise $600 from ticket sales. They sell adult tickets for $8 each and student tickets for $5 each. Let x represent the number of adult tickets and y represent the number of student tickets. The equation to represent the number of tickets sold to reach their goal, 8x+ 5y = 600, is graphed below. If 40 adult tickets are sold, how many student tickets must be sold to reach their goal?
http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-A09/a/assessments/L-LinesCoordinatePlaneUnitExam/Geometry_Unit3_Exam_100q.gif

Question

Your school drama club is putting on a play and hopes to raise $600 from ticket sales. They sell adult tickets for $8 each and student tickets for $5 each. Let x represent the number of adult tickets and y represent the number of student tickets. The equation to represent the number of tickets sold to reach their goal, 8x+ 5y = 600, is graphed below. If 40 adult tickets are sold, how many student tickets must be sold to reach their goal?
http://curriculum.kcdistancelearning.com/courses/GEOMx-HS-A09/a/assessments/L-LinesCoordinatePlaneUnitExam/Geometry_Unit3_Exam_100q.gif

anonymous · Answer

x=40 so you reduce your two variable equation into one so you can solve for y, which is the number of student tickets need to raise $600.

So, 8(40) + 5y = 600

Solve and get,
320 + 5y = 600
5y = 280
y = 56 student tickets

anonymous · Answer

Not sure what your graph is for but if you have to create one, you have to find the intercepts. Meaning, find out how many student tickets you would need to sell if you sold no adult tickets (x = 0). Then find out how many adult tickets you would need to sell if you sold no adult tickets (y = 0).