Question

3^4x2=27^x-1

Answer 1

Do you want us to graph it or solve for a solution?

Answer 2

solve please

Answer 3

Let me get a pen and paper. No one snipe me, please.

Answer 4

Is this the correct equation?

\[3^2 * 2 = 27^2 -1\]

Answer 5

\[\huge 3^{4x^2} = 27^{x-1}?\]

is that it? im not sniping dont worry lol

Answer 6

It's fine, lgb, I'm just trying to figure out what he's asking.

Answer 7

He doesn't use the correct form when righting equations so it's hard to decipher.

Answer 8

*Writing.

Answer 9

this is interesting :)

Answer 10

lgb has the correct question, so letting go of the bases it becomes \[4x ^{2} = 3\left( x-1 \right)\]

Answer 11

x = 0.11.

Answer 12

hmm

Answer 13

how did you get that?

Answer 14

I did the division on a calculator and not in fraction form.

Answer 15

Want me to show steps?

Answer 16

4x^2 = 3x - 3

4x^2 - 3x + 3 = 0

should be a quadratic formula

Answer 17

I didn't use the quadratic formula. Can you please explain, lgb?

Answer 18

the answer is x=1.
(3^3)^(x-1)
4x^2=3^(3x-3)

Answer 19

I'm a girl by the way.

Answer 20

I disagree with you jesana, that equation cannot be defined as it is, and therefore has no roots for x, it is prime.