A conical tank (with vertex down) is 10 feet across the top and 12 feet deep. If water is flowing into the tank at a rate of 10 cubic feet per minute, find the rate of change of the depth of the water when the water is 8 feet deep.
Given: V= (pi/3)(r^2)h

Question

A conical tank (with vertex down) is 10 feet across the top and 12 feet deep. If water is flowing into the tank at a rate of 10 cubic feet per minute, find the rate of change of the depth of the water when the water is 8 feet deep.
Given: V= (pi/3)(r^2)h

lgbasallote · Answer

is this related rates of differential calculus?

anonymous · Answer

Yes. ^

anonymous · Answer

So far I have this, but I feel like I'm messing something up

compassionate · Answer

I will answer all these within an hour, don't worry about the test, just keep the tab open or mark it so you can take it later. How many attempts have you given at the test? If so just close it and I'll respond with a written explanation of all of these with a short tutorial. At the moment I am working on something really important, however, I can stop what I'm doing if you need help ASAP.

anonymous · Answer

I'm not taking a test.

compassionate · Answer

Alright, I'll send you a tutorial on this shortly. Please be patient as I have other students to teach.

anonymous · Answer

Okay. FWIW I only have one question...

compassionate · Answer

Okay, what is it

anonymous · Answer

The question I posted above, starting this thread. Lol.

anonymous · Answer

It's not of much priority given it's homework and not a test, so get back to what you're doing and I'll try to watch khanacademy or something.

compassionate · Answer

I have to help another girl at the moment. Watch KhanAcademy is a great idea.

anonymous · Answer

@Compassionate

compassionate · Answer

^ What is that?