Question

what is one of the real number values that must be excluded from the domain of the function:
g(x) = (3x-6)/(x^2-7x+12)


What does that mean and how do you solve it?

Answer 1

set the bottom equal to 0 and solve for x

Answer 2

and how do i make it equal 0???

Answer 3

factor

Answer 4

(x-3)(x-4)

Answer 5

The denominator cant be zero so you have to find the x values for which the denominator equals 0.
Those are the numbers which must be excluded from the domain