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Mathematics 11 Online
OpenStudy (anikate):

simplify: x^9+ 64

OpenStudy (anonymous):

(x^3+4)(x^6-4x^3+16)

OpenStudy (anikate):

ok

OpenStudy (anikate):

how?

OpenStudy (anonymous):

sum of cube formula

OpenStudy (anikate):

can you plz help me with one more?

OpenStudy (anonymous):

if i can

OpenStudy (anikate):

ok a^2n -64

OpenStudy (anikate):

one more after this and then can you plz tell me the sum of cube formula.

OpenStudy (anonymous):

(a^n-8)(a^n+8)

OpenStudy (anikate):

next

OpenStudy (anonymous):

a^3 + b^3 = (a + b)(a^2 – ab + b^2)

OpenStudy (anikate):

A designer preparing to paint a wall found its area to be 3x^2 -2x -5 square feet. Find the length and width of the rectangular wall.

OpenStudy (anonymous):

(3x-5)(x+1) are length and width

OpenStudy (anonymous):

because area = bh

OpenStudy (anonymous):

so that area function has to equal the two i gave u

OpenStudy (anikate):

what is (x+1) Could you please explain this

OpenStudy (anonymous):

it can either be length or width

OpenStudy (anonymous):

if it is length then the other is width

OpenStudy (anikate):

where did you get (x+1) from?

OpenStudy (anonymous):

factoring the area function gives those two

OpenStudy (anikate):

what's the area?

OpenStudy (anonymous):

the function you gave me

OpenStudy (anikate):

what did you do to get (x+1)?

OpenStudy (anonymous):

by factoring 3x^2 -2x -5

OpenStudy (anonymous):

the factors are your width and length and 3x^2 -2x -5 is your area

OpenStudy (anikate):

ok a few more. these are a bit easier but I swear I will give you at least 4 medals

OpenStudy (anikate):

2x+10/x+5

OpenStudy (anikate):

how do we simplify that?

OpenStudy (anonymous):

divsion

OpenStudy (anonymous):

which gives u 2

OpenStudy (anikate):

can you plz show me

OpenStudy (anikate):

o

OpenStudy (anikate):

wait how ?

OpenStudy (anikate):

what is 2x/2

OpenStudy (anonymous):

2(x+5)/(x+5)

OpenStudy (anonymous):

u factor and cancel like terms

OpenStudy (anikate):

so i would cancel out x from 2x

OpenStudy (anonymous):

no

OpenStudy (anonymous):

u cancel out x+5 from bottom and top

OpenStudy (anikate):

then how would I get 2?

OpenStudy (anonymous):

2(x+5)/(x+5)

OpenStudy (anonymous):

when u cancel both x+5 u get 2 remaining on the top

OpenStudy (anonymous):

(x+5)/(x+5) is the same as 1 so 2 x 1 = 2

OpenStudy (anikate):

so I must do 2x+10-x-5

OpenStudy (anonymous):

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