Mathematics
11 Online
OpenStudy (anikate):
simplify: x^9+ 64
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OpenStudy (anonymous):
(x^3+4)(x^6-4x^3+16)
OpenStudy (anikate):
ok
OpenStudy (anikate):
how?
OpenStudy (anonymous):
sum of cube formula
OpenStudy (anikate):
can you plz help me with one more?
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OpenStudy (anonymous):
if i can
OpenStudy (anikate):
ok
a^2n -64
OpenStudy (anikate):
one more after this and then can you plz tell me the sum of cube formula.
OpenStudy (anonymous):
(a^n-8)(a^n+8)
OpenStudy (anikate):
next
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OpenStudy (anonymous):
a^3 + b^3 = (a + b)(a^2 – ab + b^2)
OpenStudy (anikate):
A designer preparing to paint a wall found its area to be 3x^2 -2x -5 square feet. Find the length and width of the rectangular wall.
OpenStudy (anonymous):
(3x-5)(x+1) are length and width
OpenStudy (anonymous):
because area = bh
OpenStudy (anonymous):
so that area function has to equal the two i gave u
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OpenStudy (anikate):
what is (x+1)
Could you please explain this
OpenStudy (anonymous):
it can either be length or width
OpenStudy (anonymous):
if it is length then the other is width
OpenStudy (anikate):
where did you get (x+1) from?
OpenStudy (anonymous):
factoring the area function gives those two
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OpenStudy (anikate):
what's the area?
OpenStudy (anonymous):
the function you gave me
OpenStudy (anikate):
what did you do to get (x+1)?
OpenStudy (anonymous):
by factoring 3x^2 -2x -5
OpenStudy (anonymous):
the factors are your width and length and 3x^2 -2x -5 is your area
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OpenStudy (anikate):
ok a few more. these are a bit easier but I swear I will give you at least 4 medals
OpenStudy (anikate):
2x+10/x+5
OpenStudy (anikate):
how do we simplify that?
OpenStudy (anonymous):
divsion
OpenStudy (anonymous):
which gives u 2
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OpenStudy (anikate):
can you plz show me
OpenStudy (anikate):
o
OpenStudy (anikate):
wait how
?
OpenStudy (anikate):
what is 2x/2
OpenStudy (anonymous):
2(x+5)/(x+5)
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OpenStudy (anonymous):
u factor and cancel like terms
OpenStudy (anikate):
so i would cancel out x from 2x
OpenStudy (anonymous):
no
OpenStudy (anonymous):
u cancel out x+5 from bottom and top
OpenStudy (anikate):
then how would I get 2?
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OpenStudy (anonymous):
2(x+5)/(x+5)
OpenStudy (anonymous):
when u cancel both x+5 u get 2 remaining on the top
OpenStudy (anonymous):
(x+5)/(x+5) is the same as 1 so 2 x 1 = 2
OpenStudy (anikate):
so I must do 2x+10-x-5
OpenStudy (anonymous):
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