Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (anonymous):

factor step by step factor 32x^6 – 162.

OpenStudy (anonymous):

yay!

OpenStudy (anonymous):

\[32x^6-162\] factor out gcf \[2(16x^6-81)\]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

ONE SEC

OpenStudy (anonymous):

is that a perfect square?

OpenStudy (anonymous):

its a difference of squares

OpenStudy (anonymous):

o ok

OpenStudy (anonymous):

so it is \[2(4x^3+9)(4x^3-9)\]

OpenStudy (anonymous):

but notice we are not done

OpenStudy (anonymous):

why not

OpenStudy (anonymous):

well \[ 4x^2+9\] won't factor but the other will. Do you see it?

OpenStudy (anonymous):

because its negitive

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok so then what

OpenStudy (anonymous):

it is another difference of squares try and factor it

OpenStudy (anonymous):

2x+3)(2x-3

OpenStudy (anonymous):

yep so all together it would be?

OpenStudy (anonymous):

no idea

OpenStudy (anonymous):

wait wait wait

OpenStudy (anonymous):

you said 4x^2+9 instead of 4x^3 +9

OpenStudy (anonymous):

crap

OpenStudy (anonymous):

i blame the small writing

OpenStudy (anonymous):

so what do i do after i get 4x^3-9

OpenStudy (anonymous):

Over the rationals the answer is \[ 2 \left(4 x^3-9\right) \left(4 x^3+9\right) \]

OpenStudy (anonymous):

what are the factors

OpenStudy (anonymous):

i wrote that

OpenStudy (anonymous):

If you allow irrationals, we can factor further.

OpenStudy (anonymous):

i just miss read myself later

OpenStudy (anonymous):

true that

OpenStudy (anonymous):

what are the factors

OpenStudy (anonymous):

exactly what he wrote above

OpenStudy (anonymous):

The factors are \[ 2\\ (-9 + 4 x^3) \\(9 + 4 x^3) \]

OpenStudy (anonymous):

3 factors?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thats just the factored form?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

could you help me with another problom

OpenStudy (anonymous):

close this problem and ask a new one.

OpenStudy (anonymous):

eliassaab wants more medals

OpenStudy (anonymous):

jkjk

OpenStudy (anonymous):

opend a new one

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!