Question

(x-6)/(x^2 +4x-32) • (x-4)/(x+2) please help

Answer 1

\[
\frac{(x-6) (x-4)}{(x+2)
\left(x^2+4
x-32\right)}=\frac{(x-6)
(x-4)}{(x+2) (x-4)
(x+8)}=\frac{x-6}{(x+2)
(x+8)}

\]