Question

Log (x) + Log (x-3) = Log (3x)

Please tell me whats the procedure for this eq.

Answer 1

Log (x) + Log (x-3) = Log (3x)
Log( x(x-3)) =Log (3 x)
x(x-3) =3x

Answer 2

\[
x^2-3 x =3x\\
x^2-6x=0\\
x=0 \\
x=6\\
\]
x=0 is not acceptable. Why?

Answer 3

is it x=0 and x=6?

Answer 4

x= 0 is not good since Log[0] is not defined.

Answer 5

why? is it because it has to be x>1?

Answer 6

The answer is x=6

Answer 7

okay thanks, i didnt know about the 0 Rule, thats why i was wrong :D thank you :D

Answer 8

yw
.

Answer 9

sorry, i was looking for your Profile :)