Question

The perimeter of a standard sized rectangle is 36ft. The length is 2ft longer than the width. Find the dimensions.
W=? ft
L=? ft

Answer 1

let W = width
L = length

L + L + W + W = perimeter
L + L + W + W = 36

it also says the length is 2ft longer than width so L is 2ft longer than W

L = 2 + W

substitute that to L in that first equation

L + L + W + W = 36
(2 + W) + (2 + W) + W + W = 36
2 + W + 2 + W +W +W = 36
4 + 4W = 36
4W = 36 - 4
4W = 32
W = 32/4
W = 8

can you solve for length now?

Answer 2

10?

Answer 3

yup

Answer 4

formula for perimeter of rectangle is 2[length+width] i e p=2[l+w]. given parameters are: p=36, l=w+2 and w=w put the given parameters into the equation 2[w+2+w]=36 2[2w+2]=36 4w+4=36 4w=36-4 4w=32 w=32/4 w=8 therefore,width=8 and length=width+2=8+2=10.