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find the equation of a circle radius is 2 and through (1,2) and (3,4)
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hint \[\sqrt{(3-1)^2 + (4-2)^2} = 2r\]
Equation of Circle is given by: \[\large (x-h)^2 + (y-k)^2 = r^2\]
i started by equating 2 to the distance formula of (1,2) and (3,4) ---2 equations but then i'm now stuck because i got h+k=5
let the center by (Cx, Cy)
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