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The area of a triangular poster is 84 square feet. Its height is 2 feet shorter than the length of its base. The formula for the area of a triangle is A=1/2bh. Find the height of the triangle.
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let the width be x. then\[\frac{1}{2} \times (2-x) \times (x)=(84)\]
this isn't right
Let the height be \(h\), then the base is \(b=h+2\). Now solve equation \(\frac 12h(h+2)=84\)
\(h^2+2h-168=0\)
how did you get -168 from 84?
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I got \[h^{2}+1/2h-42\]
\(\frac 12h(h+2)=84\) Multiply both parts on 2: \(2\cdot\frac 12h(h+2)=2\cdot84\) \(h(h+2)=168\)
Ok, so remove the fraction from these problems. Thanks for your help.
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