Would it be easier to factor 12t^2-17t^-1-5=0 or to use the quadratic formula?

Question

ash2326 · Answer

Is this your equation?
$$12t^2-17t^{-1}-5=0$$

anonymous · Answer

i dont think you can use the quadratic formula in this case, as we have -ve power in this case.

anonymous · Answer

$$12t^2-17t^{-1}-5=0$$This one won't factor that well.  The problem is probably$$12t^2-17t-5=0$$

anonymous · Answer

If it is, you can use the ac-method to factor it.  Do you know how to do that?

anonymous · Answer

Yes, but that's not the method my teacher wants me to use. Thank you.

anonymous · Answer

what is the problem exactly. is it quadratic or not?

anonymous · Answer

No. it's not quadratic.

anonymous · Answer

The quadratic formula only works on quadratic equations.

anonymous · Answer

there must have been a mistake with this problem.
anyways, the equation can be reduced to cubic form.the equation has a sign change between 1 and 2. so it must have a root between these two numbers. i found it to be 1.246. the other two roots can be found by reducing this cubic equation into quadratic equation and they come out to be imaginary.