Solve the system of equations. y = 3x + 1 4y = 12x + 4
write out your equations like this: 4y= 12x+4 y-3x=1. You see what I did? I subtracted the 3x so the variables could line up
4y=12x+4
oops sorry i messed up
its the same equation
y-3x=1 4y-12x=4
now variables are lined up
-1(y-3x=1). To cancel one of the variables out, make it a negative. In this case, I chose the y by itself, so multiply the whole equation by -1. Then you get, -y+3x=-1
4y-12x=4 -y+3x=-1.. Can you answer it from here?
...?
I guess that didn't do anything
what do i do if all the variable are not the same
wait i think i got it
quick question. Are you looking for the x or y?
it just says solve the system of equations
really?
welll if you get y by itself, you end up getting the equation, y=3x+1
I have to go now.. sorry! You can ask someone else for help!
can you not help anymore??
it is the same equation it has infinite many solution
both equations are the same! the 2nd one is just the 1st eq multiplied by 4.
y-3x=1 4y-12x=4 1(y-3x=1)
this is what i have
I'm back. Like I said, both end up being the same exact question... y=3x+1, which means they have infinite solutions. I kinda forgot systems.. But yeah I guess that's my answer
And ignore what I did with all that math
oh ok..so no solution
@coolaidd there is solution just let any of the variable arbitrary let y=t then solveequation 1 for x x=(t-1)/3 si solution is x=t/3-1/3 y=t it means it can have infinite many solutions whatever you want can take value of t . i hope it is clear
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