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How do I solve (2y+3)^2=9
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do you want a full answer...? or just a hint ?!
A hiint would be nice
It takes that long to type a hint?
kk ! add -9 both sides you'll have \[(2y+3)^2-9=0\] and try to use this...\[a^2-b^2=(a-b)(a+b)\]
wher edid u get -9
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|dw:1342636456117:dw|
kk \[(2y+1)^2-9=9+-9=0\] I just added -9 to each part of the equation !
|dw:1342636518618:dw|
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