Question

Choose the slope-intercept equation of the line that passes through the point (6, 4) and is parallel to y = one thirdx - 3.

y = 3x - 14

y = one thirdx + 2

y = -3x + 22

y = -one thirdx + 8

Answer 1

Parallel to : \(y = \frac{1}{3}x - 3\)

So the slope of this line is \(\large \frac{1}{3}\)

So, m = 1/3

Use the equation:

\[\large y-y_1 = m(x-x_1)\]

\[y - 4 = \frac{1}{3} ( x - 6)\]

\[\large y - 4 = \frac{1}{3}x - 2\]

Add 4 both the sides and find the equation..