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Can you explain why the problem below is solved the way it is?
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\[2b ^{2}+7b+3\] \[2b ^{2}+1b+6b+3\] \[b(2b+1)+3(2b+1)\] \[(b+3)(2b+1)\]
I don't understand the second step. Why is \[7b\] split into \[1b\] and \[6b\]?
multiply b^2 's coefficient with last term wt do u get?
What..?
u know b^2's coefficient ?
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coefficient means numerical value attached with variable
so wt is coefficient of b^2
tell me
@0mgl0la
ok np:) b^2's coefficient is 2 & last term is 3 now multiply wt do u get?
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