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Mathematics 9 Online
OpenStudy (anonymous):

Can you explain why the problem below is solved the way it is?

OpenStudy (anonymous):

\[2b ^{2}+7b+3\] \[2b ^{2}+1b+6b+3\] \[b(2b+1)+3(2b+1)\] \[(b+3)(2b+1)\]

OpenStudy (anonymous):

I don't understand the second step. Why is \[7b\] split into \[1b\] and \[6b\]?

OpenStudy (maheshmeghwal9):

multiply b^2 's coefficient with last term wt do u get?

OpenStudy (anonymous):

What..?

OpenStudy (maheshmeghwal9):

u know b^2's coefficient ?

OpenStudy (maheshmeghwal9):

coefficient means numerical value attached with variable

OpenStudy (maheshmeghwal9):

so wt is coefficient of b^2

OpenStudy (maheshmeghwal9):

tell me

OpenStudy (maheshmeghwal9):

@0mgl0la

OpenStudy (maheshmeghwal9):

ok np:) b^2's coefficient is 2 & last term is 3 now multiply wt do u get?

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