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Mathematics 19 Online
OpenStudy (anonymous):

help me please ? anyone ?

OpenStudy (anonymous):

what is your question?

OpenStudy (anonymous):

The graph of which quadratic equation is shown below?

OpenStudy (anonymous):

the zeros are at 1 and 3

OpenStudy (anonymous):

so the equation must be:\[c(x-1)(x-3)\] where c is a constant

OpenStudy (anonymous):

if you FOIL you get\[x^2 - 4x +3\]

OpenStudy (anonymous):

multiplied by an unknown constant

OpenStudy (anonymous):

however, in this case, the y-intercept is 3, the vertex is at 2, and it opens upward

OpenStudy (anonymous):

so c is actually 1

OpenStudy (anonymous):

so you have: \[1(x^2 - 4x + 3) = x^2 - 4x +3\]

OpenStudy (anonymous):

oakyy thanks

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