Question

y varies inversely as twice x. When x = 3, y = 8. Find y when x = 2.

Answer 1

y varies inversely as twice x so
\[y = \frac{k}{2x}\]
when x = 3 then y = 8
\[8 = \frac{k}{2(3)} \implies 8 = \frac{k}{6} \implies 48 = k\]
find y when x= 2
\[y = \frac{k}{2x}\]
\[y = \frac{48}{2(2)}\]
\[y = \frac{48}{4}\]
\[y = 12\]
do you get that?