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If x^2 + 2xy + y^2 = 25, x + y > 0 and x - y = 1, then x =
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idk
x^2 + 2xy + y^2=(x+y)^2 So, how can we use that?
i guess you can solve for y and then plug in
I had this idea: x^2 + 2xy + y^2=25 So then: (x+y)^2=25 So: x+y=5 OR x+y=-5 -5 can't be because x+y>0 So then: x+y=5 And using this: x - y = 1 We add them: 2x=6 X=3 Makes sense?
@lawls Does this makes sense? Feel free to ask! :)
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yeah it does. i got the same answer. thanks :)
You are welcome! Glad to help you! :)
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