Question

What is the third–degree polynomial function such that f(0) = –24 and whose zeros are 1, 2, and 3?

Answer 1

f(0)=4(x-1)(x-2)(x-3)=-24

Answer 2

you can convert that into a cube function

Answer 3

General

\[f(x)=a(x-1)(x-2)(x-3)
\\f(0)=a(0-1)(0-2)(0-3)=-24 \\
\therefore \ a = 4\]

Answer 4

f(x) = 4x3 – 24x2 + 44x – 24

f(x) = 2x3 – 24x2 + 22x – 24

f(x) = 4x3 + 24x2 – 44x – 24

f(x) = 2x3 + 24x2 – 22x – 24
-these are the options .

Answer 5

a