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solve by the subst. method : y=3x-12 2x-3y=-13
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do you know what to do first?
no
Pu the y value that is 3x - 12 in the second equation and the solve..
We can do this: 2x-3*(3x-12)=-13 And how do we continue now?
Distribute 3 inside the parenthesis..
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so it becomes 2x-9x+36=-13
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