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Mathematics 19 Online
OpenStudy (anonymous):

f'(x) = 1/ (x^2 + 1)^2 - 3x^2 Does this function have any roots besides zero? Will functions with a constant numerator ever have a root besides zero?

OpenStudy (anonymous):

I realize this is kind of a dumb question because I found zero is not a zero for this function...nevermind

OpenStudy (anonymous):

OpenStudy (anonymous):

Good old Mathematica!

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