A cube of side length 10 cm is intersected by a plane perpendicular to the base as shown.

Part 1: Describe the shape of the cross section formed by the cube and the intersecting plane.
Part 2: Find the perimeter of the cross section. Show your work.

Question

A cube of side length 10 cm is intersected by a plane perpendicular to the base as shown. 



Part 1: Describe the shape of the cross section formed by the cube and the intersecting plane.
Part 2: Find the perimeter of the cross section. Show your work.

zeesbrat3 · Answer

attachment

ganeshie8 · Answer

what shape you think ?

zeesbrat3 · Answer

Well its definitely a triangle.

zeesbrat3 · Answer

it makes a triangle..

ganeshie8 · Answer

i see a rectangle of  10 x 5

ganeshie8 · Answer

it is asking for shape of "cross-section"

ganeshie8 · Answer

that shape is grayed in the pix. check once

zeesbrat3 · Answer

Oh, not what it makes. So ya a rectangle, but where did you find the 10x5? The height is 10 I know, but wheres the 5?

ganeshie8 · Answer

ill explain that. but first, do u get what cross-section means ?

zeesbrat3 · Answer

Its what intersects the shape, from the insides, right?

ganeshie8 · Answer

thats right !
think of it as, you are cutting the CUBE with the PLANE. 

cross-section is just the interface between the two

ganeshie8 · Answer

width 5...  isnt it just the hypotenuse of the corner triangle ?

zeesbrat3 · Answer

The hypotenuse would be on the other side of the corner..

zeesbrat3 · Answer

Wait, would you use Pythagorean theorem to find the missing side? Because if it is a cube, then the missing sides would be 3 and 4 wouldnt they?

ganeshie8 · Answer

thats right ;)

zeesbrat3 · Answer

:) I just realized that! So then 2(5)+ 2(10)=30

ganeshie8 · Answer

attachment

ganeshie8 · Answer

yep ! thats the perimeter of cross-section

zeesbrat3 · Answer

Thanks!!

ganeshie8 · Answer

np