I'm *pretty* sure the answer here is D Which expression shows the value of cot x°? hypotenuse ÷ adjacent adjacent ÷ opposite hypotenuse ÷ opposite adjacent ÷ hypotenuse
nope nope not D
Unless you meant cos(x)
How different is Cos and Cot? lol
rebecca honestly there is no way for me to help you with this problem other than giving you the trig ratios which will give the answer
No it was cot xº
This was the problem. It was the way it was given to me. If you don't mind showing me, I'm more than willing to learn :)
cot x = adjacent /hypotenuse option d and m sure about it
Myin just said not D :/
\[\sin(x)=\frac{opp}{hyp} , \cos(x)=\frac{adj}{hyp} , \tan(x)=\frac{opp}{adj}\] \[\csc(x)=\frac{hyp}{opp}, \sec(x)=\frac{hyp}{adj}, \cot(x)=\frac{adj}{opp}\]
*takes notes* yes, yes.
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