Question

What is the equation of the line passing through (–6, 1) and perpendicular to the line y = –3x + 1 in slope-intercept form?

Answer 1

these are my choices
y = 3x + 4

y = one-thirdx + 3

y = –3x – 6

y = negative one-thirdx – 5

@CarlosGP

Answer 2

Try it yourself with instructions given: for Y=mX+B, the perpendicular has to be:
Y=(-1/m)X+C, calculate the slope -1/m and the value C(substituting the values of the point given)