Question

Find 2 numbers whose sum is 64 and whose difference is 42.

Answer 1

i got 53,11

Answer 2

Yes you are absolutely right..

Answer 3

ok

Answer 4

n1 + n2 =64
|n1 - n2| = 42
from 1º equation: n1 = 64 -n2
put it in 2º equation: |64-n2 -n2| = 42
solve for n2: |64 -2n2| = 42
so 2 posibilities: 64-2n2=-42 and 64-2n2=42
106=2n2
n2 = 53
and
64 -42 =2n2
2n2=22
n2=11

Answer 5

k