Question

This problem is Differentiation of Inverse Trigonometric Functions:
y = arc sec squareroot(4x+1)

Answer 1

\[y = arc \sec \sqrt{4x+1}\]

Answer 2

\[\frac d{dx}\sec^{-1}u=\frac1{|u|\sqrt{1-u^2}}\frac {du}{dx}\]

Answer 3

let\[u=\sqrt{4x+1}\]

Answer 4

i need the answer so i will know if my answer is right.

Answer 5

show me what you got so I can tell you

Answer 6

i'm in the simplifying part already...