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Calculate following derivatives: \[\Large \frac{d}{dx} \int_0^{x^{2}} dt \frac{\exp t}{t^{2}+1}\]
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\[ 2x\frac {e^{x^2}}{x^4+1} \]
FTC and Chain Rule
Mr Saab is it end solution so that i can write it tomorrow on exam if same question appears?
yes
\[ \frac {d}{dx}\int_{v(x)}^{u(x)} f(x)dx = f(u(x)) u'(x)- f(v(x)) v'(x) \]
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In your case \[ v(x)=0\\ u(x)=x^2 \]
ok thank you very very much mr Saab
\[\frac {d}{dx}\int_{v(x)}^{u(x)} f(t)dt = f(u(x)) u'(x)- f(v(x)) v'(x)\] A small misprint
ok thank you
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