Question

What is the equation in standard form of the line which passes through (4, –2) and has a slope of –3?

Answer 1

write the equation in point-slope form i.e. like y=m(x-x1)+y1
so in point-slope form, equation is y=-3(x-4)+(-2)
y=-3x+12-2
y=-3x+10
Then rewrite in standard form:
3x+7=10

Answer 2

note that in point-slope form, m=gradient, x1 and y1 are coordinates of a point on the line, in this case 4 and -2

Answer 3

7?

Answer 4

dont you have to do something else to seven?? :?

Answer 5

Oh yeah, sorry, we had y=-3x+10
So in standard form it should be 3x+y=10
sorry :)

Answer 6

oh O.O!
OK :) THANKS YOU !

Answer 7

you're welcome. :)