What is the equation in standard form of the line which passes through (4, –2) and has a slope of –3?

Question

allank · Answer

write the equation in point-slope form i.e. like  y=m(x-x1)+y1
so in point-slope form, equation is   y=-3(x-4)+(-2)
y=-3x+12-2
y=-3x+10
Then rewrite in standard form:
3x+7=10

allank · Answer

note that in point-slope form, m=gradient, x1 and y1 are coordinates of a point on the line, in this case 4 and -2

anonymous · Answer

7?

anonymous · Answer

dont you have to do something else to seven?? :?

allank · Answer

Oh yeah, sorry, we had y=-3x+10
So in standard form it should be 3x+y=10
sorry :)

anonymous · Answer

oh O.O!
 OK :) THANKS YOU !

allank · Answer

you're welcome. :)