Question

Let log[b] A=1, log[b] C=3, log[b] D=4
What is the value of log[b] (A^5 C^2/D^6)

Im confused can someone explain how to do this?

A. 26
B. 0
C. There isn't enough information to answer the question.
D. -13

Answer 1

\[\log_b (\frac{A^5 C^2}{D^6}) \implies \log_b A^5 + \log_b C^2 - \log_b D^6 \implies 5\log_b A + 2\log_b C - 6\log_b D\]
does that help?

Answer 2

Yeah and I got -13

Answer 3

yup i got the same :D