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translate each problem into an equation. (1) State College has 620 students. (2) There are 20 more women than men. How many women are there?
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x+y=620
y =women x=man y=x+20
thanks
Do you know what do we have to do next?
um not quite sure
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x+y=620 y=x+20 We can take the second equation and plug it on the first one. Like this: x+(x+20)=620 How can we continue now?
distribute your x then solve by adding like terms first
then 20 - from both sides that leaves 2x=600 now divide
300?
yes
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You got it! Well done!
good job!
thankss
But x is the number of man, right?
How do we get y now?
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y=x+20 y=300+20 y=320 320 women is the answer.
Any doubt?
thats what i got
Awsome! Hope I've helped you! PD: Thanks for the "Best response" :D
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