Find the inverse of the one-to-one function.
f(x) = 2x+5/7
A. f-1(x) =7/2x+5
B. f-1(x) =7/2x-5
D. f-1(x) =7x-5/2
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OpenStudy (anonymous):
you want the answer or how to find it ?
OpenStudy (anonymous):
We can't give answers, we are supposed to help the student with the method.
OpenStudy (anonymous):
solve for x and change to y
OpenStudy (anonymous):
f(x) = 2x+5/7
How can we solve that for x?
OpenStudy (anonymous):
I did it myself and got y=2x+5/2 but that was wrong
But this is what I did
y=2x+5/7
x=2y+5/7
y=7x+5/2
I don't know what I did wrong so no I want to know how to do it
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OpenStudy (anonymous):
you dont change y for x in the beginning
OpenStudy (anonymous):
you have to solve for x first then change at the end
OpenStudy (anonymous):
for some reason i am really stuck do I make them fractions
OpenStudy (anonymous):
like this y= 2x/7 + 5/7
OpenStudy (anonymous):
or do I multiply the top by 7
like this
y=14x + 35
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OpenStudy (anonymous):
u subtract 5/7 first
OpenStudy (anonymous):
so 5/7 = 2x
OpenStudy (anonymous):
y-5/7
OpenStudy (anonymous):
so it is like this
y-5/7 = 2x
OpenStudy (anonymous):
ya and you solve for x
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