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Blake has a total of 64 DVD's and CD's. If the number of CD's is eight more than three times the number of DVD's, how many DVD's does he have?
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Let the number of DVDs = x and the number of CDs = y According to the question x+y=64, Therefore x = 64-y y=3x+8 Now substitute x value y = 3(64-y)+8 y=192-3y+8 3y+y=200 4y=200 y=200/4 = 50 Number of DVDs = 64-50 = 14 Number of CDs = 50
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