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Mathematics 9 Online
OpenStudy (anonymous):

What is the equation of this circle?

OpenStudy (anonymous):

OpenStudy (anonymous):

@rafabc02

OpenStudy (anonymous):

You can use this: \[(x-a)^2+(y-b)^2=r^2\] r is the radius: (a, b)=center

OpenStudy (anonymous):

0,1?

OpenStudy (anonymous):

is the center i mean

OpenStudy (anonymous):

That's right!

OpenStudy (anonymous):

And what about the radius?

OpenStudy (anonymous):

2

OpenStudy (anonymous):

Excellent! So the equation is?

OpenStudy (anonymous):

x2 + (y – 1)2 = 2

OpenStudy (anonymous):

?

OpenStudy (anonymous):

LHS is right..

OpenStudy (anonymous):

so i'm right?..

OpenStudy (anonymous):

r = 2.. So according to the equation \(r^2\) = ???

OpenStudy (anonymous):

x^2+(y-1)^2=2^2

OpenStudy (anonymous):

RHS is not right..

OpenStudy (anonymous):

x2 + (y – 1)2 = 4?

OpenStudy (anonymous):

\[x^2+(y-1)^2=4\]

OpenStudy (anonymous):

Yes you are right now..

OpenStudy (anonymous):

Well done!

OpenStudy (anonymous):

thanksss both of you again!

OpenStudy (anonymous):

Welcome dear..

OpenStudy (anonymous):

You are welcome! Glad to help kind people like you! :)

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