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Simplify (m^3/3n)/^(-m^4 /9n2)
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this questions makes no sense
^ you are missing something
Do you mean (m^3/3n)/(-m^4/9n^2) ?
(m^3/3n)/(-m^4 /9n^2)
yea sorry
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\[\frac{(m^3/3n)}{(-m^4 /9n^2)}\]
\[\frac{(a/b)}{(c/d)}=\frac{a}{b}*\frac{d}{c}\]
See how we can rewrite this?
so the answer be 3/mn
-3n/m
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\[\frac{m^3}{3n} \frac{9n^2}{-m^4} = -\frac{3n}{m}\]
can u help me on this one (6y^2 -6/ 8y^2 +8y)/(3y -3 / 4y^2 + 4y)
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