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lny=9t-8; solve for y?
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y=e^(9t-8)
\(\ln y = x => y = e^x\) \(\ln y = 9t-8 => y = ?\)
i think thats the right answer but how did you get it?
simple log lindsay \[\log_{a}b=c \] can be also be written as \[a^c=b\]
thanks! solve 2^x+2^-x=3
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