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Mathematics 11 Online
OpenStudy (anonymous):

Find the requested function value meeting all of the given conditions. sinx=sqrt3/2 and tanx>0. find cosx

OpenStudy (anonymous):

as tanx is +ve, cosx must be positive. sinx=sqrt(3)/2. \[cosx=\sqrt{1-\sin^{2}x}\]

OpenStudy (anonymous):

so would the answer be 1/2?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thanks!

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