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Mathematics 31 Online
OpenStudy (anonymous):

this is Square root of 141?

OpenStudy (anonymous):

OpenStudy (anonymous):

\(x^2=25^2-22^2=(25-22)(25+22)=3*47=141 \) so u r quite right

OpenStudy (lgbasallote):

\[x = \sqrt{25^2 - 22^2}\] \[x = \sqrt{ 625 - 484}\] \[x = \sqrt{141}\]

OpenStudy (anonymous):

thank you

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