Question

What is the smallest possible value of f(x) if f(x)=Ѵ(3x-2)?
A) 1
B) 0
C) 1/5

Answer 1

f(x) ?

Answer 2

if fx = root (3x -2)

Answer 3

I don't get it.

Answer 4

me neither

Answer 5

The value under the radical must be positive. so 3x-2>=0 or x>=2/3. minimum is for x=2/3 so \( \sqrt{3x-2}=\sqrt{3\frac{2}{3}-2}=0 \)