Pulley based Question
{H C V - Q.27 - Chapter 5 [NLM] .}

Question

Pulley based Question 
{H C V - Q.27 - Chapter 5 [NLM] .}

maheshmeghwal9 · Answer

attachment

maheshmeghwal9 · Answer

I didn't gt the second part of the question:/

However I gt the acceleration of blocks which is $$4.28 \space m/s^2 \approx  4.3 \space m/s^2.$$

anonymous · Answer

awcond part of the question is if rope breaks what would be the motion of m1
add it as m1g+F=5kg*9.8+1N
then you may find acceleration to define how it is falling down

anonymous · Answer

@maheshmeghwal9 i think what the second part says is this:
if the string breaks, tension will no longer be acting on m1. then the only forces acting on m1 will its weight and F, both vertically downwards.
so, the eq will be m1*g + F = m1*a. 
the motion of m1 will be: m1 moving downwards with acceleration a.

anonymous · Answer

lol viadehi explained it better good guddi. . .

anonymous · Answer

'good guddi'! lol thanks!

maheshmeghwal9 · Answer

@Vaidehi09 thanx a lot:D

anonymous · Answer

happy to help :)