Question

help pre-cal!! picture attached!

Answer 1

@sai1234

Answer 2

start with
y= x^3 + 2

solve for x
then rename x to y and y to x

Answer 3

im confused

Answer 4

do you know how to "solve for x" in
y= x^3+2 ?

that means get x by itself

Answer 5

no

Answer 6

you start by add -2 to both sides.

Answer 7

x^3 = y-2

now take the cube root of both sides

\[ x=\sqrt[3]{y-2}\]

now rename x and y
\[y= \sqrt[3]{x-2}\]